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For #21... look at the diagram... what if I renamed 'r' to 'a' and 'd' to 'b' and 'r+h' was = 'c'? Should be a theorem close to your heart, right?
For #22, I assume you figured XP=3rad3 and AB=6 (based on Thm 9-13). You should be able to use Thm 9-10 (Case III) to set up an equation for angle-P. If you call arc-XA 'x' you should see a relationship to arc-AB, since chord-XA is cong. to chord-AB. It's really just some fun with Algebra.
btw, for #22 on pg 360, you should set up a proportion where 7:x as 3:y and solve for x in terms of y or vice versa. Then you can use Thm 9-10 and have MORE FUN with Algebra!
I understand both...#21 was simple now that I think about it...#22 I had to look really hard for 60 30 90 triangles, got the radius and it was simple from there with Pythag...For #22 I got AB=6, the distance from O to AB is 3rad3, and the radius is 6
I know this isnt for chapter 9.... It is actually for chapter 10.. I was wondering what the Homework is that is due on 5/11/10. All I know is that there is a teat on tues
i dont understand #22, how to get the distance to the chord or how to get the radius. I also dont get the first part of 21
ReplyDeleteCHRIS
For #21... look at the diagram... what if I renamed 'r' to 'a' and 'd' to 'b' and 'r+h' was = 'c'? Should be a theorem close to your heart, right?
ReplyDeleteFor #22, I assume you figured XP=3rad3 and AB=6 (based on Thm 9-13). You should be able to use Thm 9-10 (Case III) to set up an equation for angle-P. If you call arc-XA 'x' you should see a relationship to arc-AB, since chord-XA is cong. to chord-AB. It's really just some fun with Algebra.
btw, for #22 on pg 360, you should set up a proportion where 7:x as 3:y and solve for x in terms of y or vice versa. Then you can use Thm 9-10 and have MORE FUN with Algebra!
lmk how things go!
Mr. C.
I understand both...#21 was simple now that I think about it...#22 I had to look really hard for 60 30 90 triangles, got the radius and it was simple from there with Pythag...For #22 I got AB=6, the distance from O to AB is 3rad3, and the radius is 6
ReplyDeleteCHRIS
did you get #22 from pg 360?
ReplyDeleteMr. C.
I dont understand #17 on the chapter test...do you have to factor
ReplyDeleteCHRIS
Nope... it's just a secant and a tangent, i.e. Thm 9-10 Case III...
ReplyDelete(PS)(PR) = (PT)^2
so...
18x = 12^2
18x = 144
x = 8
right??
I know this isnt for chapter 9.... It is actually for chapter 10..
ReplyDeleteI was wondering what the Homework is that is due on 5/11/10.
All I know is that there is a teat on tues
see the new post for Chapter 10...
ReplyDelete