Thursday, December 10, 2009
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This Blog exists for the collective benefit of all geometry students. All questions are welcome. The more specific your question (including your own attempts to answer it) the better.
EVEN MORE WELCOME ARE ANSWERS FROM FELLOW STUDENTS. BLOG ON!
You WILL NOT have access to your bibles during the quiz, so make sure you study and understand the concepts of the theorems in sections 5-1 thru 5-3. Word-for-word memorization or Thm numbers are not required... CONCEPTS MAN, CONCEPTS!!
ReplyDeleteHere's some help (the theorems are numbered differently, but the concepts are what counts)
http://www.phschool.com/atschool/academy123/english/academy123_content/wl-book-demo/ph-416s.html
FREE STUFF: There is DEFINITELTY A QUESTION on the test that will require you to know that:
"If one pair of opposite sides of a quadrilateral is both congruent and parallel, then the quadrilateral is a parallelogram"
so make sure you and your friends know that.
Any questions on the homework? Help is just a click away... though I might not be able to answer until late tonight, so maybe some of you can answer each others questions!! (what a concept)
Thanks that helps a lot.
ReplyDeleteI didnt get #8 on the self test on the hw. could someone help me out?
ReplyDeleteHere's one of several possible narrrative proofs:
ReplyDeleteThe opp angles of a prllgrm are cong... therefore the bisectors create sets of cong angles.
angl-SPR and angl-QRP are alt int. angles (thrfore cong).
seg-RP is reflexive to seg-PR (duh!).
Wow, already you have ASA with tri-XPR and tri-YRP.
So seg-RY cong seg-PX and seg-PY cong seg-RX.
Thrfore RYPX is a prllgrm since it is a quadrltrl with two pairs of opp cong sides (Thm 5-4).
Got one better than that? Post it!
Ca-peesh?
MrC