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hmmm... no questions, huh? Well then, the first student who can LUCIDLY describe the how the answer to #33 can be derived, is the winner of extra credit, which can be applied to either the first OR second marking period!! WOo-hoo!!
i don't get how to do #33 or 25 or 31 or 29 i think could anyone explain this? O and how do you get your name to show up on this cuz i don't know how -Natasha
(N.B. commenting anonymously is fine, just leave your name as you did. If you join the blog as a member, you'll be able to use your id when you comment.)
As far as your question goes, one of the challenges here is to see where you can create congruent triangles, which will then chear the way for you to use CPCT to prove other "thingeroos" congruent, isosceles or whatever.
In pg 139#31, there is certain info given. Can you see that trngls JKM and JKN are congruent based on SAS? You should be able to see that fairly clearly. Well, now that you know that, you can use CPCT to show that JM cong JN. Therefore, trngl JMN is isosceles, ca-peesh?
You can use the same logic "south" of the plane to prove that trngl LMN is isosceles, ca-peesh?
As for 139#33, gosh, this is such fun. You KNOW that the int. angles of the REGULAR pentagon are 540/5 or 108 degrees, right? And, obvia-mundo, the square consists of 90 degree angles, right? So just keep going... trngl AED is isos, right? Therefore you know that angle-EDA and angle-EAD are cong and sum to ??. Therefore each angle = ??. Also, you know that trngl FEA is isos, AND furthermore you should be able to calculate the measure of angl-FEA. Just keep on going to answer the questions... did this help?
Do you see the progression? We just keep building by using the triangle congruence postulates and CPCT.
hey i have a question for the homework due tomorow,11/19, i did not exactly understand how to go about proving the problem on page 144 i think it was question 4 in the written excersizes and it would be helpful if we could run through the proof tomoro in class
Well, I'll "plan" the proof and you can do it, OK? Pause after you read each line below and see if it's enough of a hint for you to continue on your own.
Based on the given, we have tri-RSA cong tri-ATR based on SSS, right? (since RA cong AR reflexive, right?).
If we can make tri-OSR cong tri-OTA, then we would have an isosceles tri-OST which would mean that angl-TSA and angl-STR are congruent based on Thm 4-1, right?
Well (geepers) TA cong SR and angl-ATR cong angl-RSA, AND (yippee) we gotsk ourselves vertical angles at O... so, can you see that tri-OSR cong tri-OTA based on AAS?
CPCT says that OT cong OS... and now you have your isosceles tri-OST!! What FUN!!
hmmm... no questions, huh? Well then, the first student who can LUCIDLY describe the how the answer to #33 can be derived, is the winner of extra credit, which can be applied to either the first OR second marking period!! WOo-hoo!!
ReplyDeletei don't get how to do #33 or 25 or 31 or 29 i think could anyone explain this? O and how do you get your name to show up on this cuz i don't know how
ReplyDelete-Natasha
(N.B. commenting anonymously is fine, just leave your name as you did. If you join the blog as a member, you'll be able to use your id when you comment.)
ReplyDeleteAs far as your question goes, one of the challenges here is to see where you can create congruent triangles, which will then chear the way for you to use CPCT to prove other "thingeroos" congruent, isosceles or whatever.
In pg 139#31, there is certain info given. Can you see that trngls JKM and JKN are congruent based on SAS? You should be able to see that fairly clearly. Well, now that you know that, you can use CPCT to show that JM cong JN. Therefore, trngl JMN is isosceles, ca-peesh?
You can use the same logic "south" of the plane to prove that trngl LMN is isosceles, ca-peesh?
As for 139#33, gosh, this is such fun. You KNOW that the int. angles of the REGULAR pentagon are 540/5 or 108 degrees, right? And, obvia-mundo, the square consists of 90 degree angles, right? So just keep going... trngl AED is isos, right? Therefore you know that angle-EDA and angle-EAD are cong and sum to ??. Therefore each angle = ??. Also, you know that trngl FEA is isos, AND furthermore you should be able to calculate the measure of angl-FEA. Just keep on going to answer the questions... did this help?
Do you see the progression? We just keep building by using the triangle congruence postulates and CPCT.
For problem #11 on page 137, are we supposed to use the picture displayed for #13 or are we supposed to make up our own?
ReplyDelete-Dalpe
You should use the picture (AND THE PLAN) from page 135, eh?
ReplyDeletehey i have a question for the homework due tomorow,11/19, i did not exactly understand how to go about proving the problem on page 144 i think it was question 4 in the written excersizes and it would be helpful if we could run through the proof tomoro in class
ReplyDeleteWell, I'll "plan" the proof and you can do it, OK? Pause after you read each line below and see if it's enough of a hint for you to continue on your own.
ReplyDeleteBased on the given, we have tri-RSA cong tri-ATR based on SSS, right? (since RA cong AR reflexive, right?).
If we can make tri-OSR cong tri-OTA, then we would have an isosceles tri-OST which would mean that angl-TSA and angl-STR are congruent based on Thm 4-1, right?
Well (geepers) TA cong SR and angl-ATR cong angl-RSA, AND (yippee) we gotsk ourselves vertical angles at O... so, can you see that tri-OSR cong tri-OTA based on AAS?
CPCT says that OT cong OS... and now you have your isosceles tri-OST!! What FUN!!
Ca-peesh?